10b^2-13bc-3c^2=0

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Solution for 10b^2-13bc-3c^2=0 equation:


Simplifying
10b2 + -13bc + -3c2 = 0

Reorder the terms:
-13bc + 10b2 + -3c2 = 0

Solving
-13bc + 10b2 + -3c2 = 0

Solving for variable 'b'.

Factor a trinomial.
(2b + -3c)(5b + c) = 0

Subproblem 1

Set the factor '(2b + -3c)' equal to zero and attempt to solve: Simplifying 2b + -3c = 0 Solving 2b + -3c = 0 Move all terms containing b to the left, all other terms to the right. Add '3c' to each side of the equation. 2b + -3c + 3c = 0 + 3c Combine like terms: -3c + 3c = 0 2b + 0 = 0 + 3c 2b = 0 + 3c Remove the zero: 2b = 3c Divide each side by '2'. b = 1.5c Simplifying b = 1.5c

Subproblem 2

Set the factor '(5b + c)' equal to zero and attempt to solve: Simplifying 5b + c = 0 Solving 5b + c = 0 Move all terms containing b to the left, all other terms to the right. Add '-1c' to each side of the equation. 5b + c + -1c = 0 + -1c Combine like terms: c + -1c = 0 5b + 0 = 0 + -1c 5b = 0 + -1c Remove the zero: 5b = -1c Divide each side by '5'. b = -0.2c Simplifying b = -0.2c

Solution

b = {1.5c, -0.2c}

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